1/(x+2)^2=-1

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Solution for 1/(x+2)^2=-1 equation: 


D( x )

(x+2)^2 = 0

(x+2)^2 = 0

(x+2)^2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:+oo)

1/((x+2)^2) = -1 // + 1

1/((x+2)^2)+1 = 0

1/((x+2)^2)+(1*(x+2)^2)/((x+2)^2) = 0

1*(x+2)^2+1 = 0

x^2+4*x+5 = 0

x^2+4*x+5 = 0

x^2+4*x+5 = 0

DELTA = 4^2-(1*4*5)

DELTA = -4

DELTA < 0

1 = 0

1/((x+2)^2) = 0

1/((x+2)^2) = 0 // * (x+2)^2

1 = 0

x belongs to the empty set

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